chapter_19
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chapter_19 [2024/09/09 23:25] – [Example of the effect of selection on recessive mutations: PKU] mike | chapter_19 [2024/09/18 17:52] (current) – [Cystic fibrosis] mike | ||
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- | <typo fs: | + | <- chapter_18|Chapter 18^table_of_contents|Table of Contents^chapter_20|Chapter 20 -> |
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In the [[chapter_18|Chapter 18]] we saw that in a population, allele frequency does not change from generation to generation, unless: | In the [[chapter_18|Chapter 18]] we saw that in a population, allele frequency does not change from generation to generation, unless: | ||
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- | If a genotype has S = 0.75, then fitness = 0.25, meaning that individuals with this genotype will reproduce at a rate of only 25% relative to an average individual. Fitness can be thought of as a combination of survival and fertility. Let's put this into the context of the Hardy-Weinberg equilibrium. Recall from [[chapter_18|Chap. 18]] that $f(\frac{A}{A})=p^2$, $f(\frac{A}{a})=2pq$, and $f(\frac{a}{a})=q^2$. | + | If a genotype has S = 0.75, then fitness = 0.25, meaning that individuals with this genotype will reproduce at a rate of only 25% relative to an average individual. Fitness can be thought of as a combination of survival and fertility. Let's put this into the context of the Hardy-Weinberg equilibrium. Recall from [[chapter_18|Chap. 18]] that $f(A/A)=p^2$, $f(A/a)=2pq$, and $f(a/a)=q^2$. |
<table Tab1> | <table Tab1> | ||
<columns 100% *100%*> | <columns 100% *100%*> | ||
^ genotype | ^ genotype | ||
- | | $\frac{A}{A}$ | $p^2$ | $p^2$ | 0 | | + | | $A/A$ | $p^2$ | $p^2$ | 0 | |
- | | $\frac{A}{a}$ | $2pq$ | $2pq$ | 0 | | + | | $A/a$ | $2pq$ | $2pq$ | 0 | |
- | | $\frac{a}{a}$ | $q^2$ | $q^2(1-s)$ | $q^2(1-S)-q^2 = -Sq^2$ | + | | $a/a$ | $q^2$ | $q^2(1-S)$ | $q^2(1-S)-q^2 = -Sq^2$ |
</ | </ | ||
< | < | ||
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- | For PKU, $q^2 = 10^{-4}$, so $q=10^{-2}$. Also, since PKU is fairly severe, | + | For PKU, $q^2 = 10^{-4}$, so $q=10^{-2}$. Also, since PKU is fairly severe, |
- | In modern times PKU can be treated by a low-phenylalanine diet so $S < 1$. This suggests that the frequency of PKU mutant alleles should start to rise at a rate $\mu = 10^{-4}$. Thus, $q$ will only increase by about a factor of 1% per generation. It will take a long time for this change in environment to have a significant effect on disease frequency. | + | In modern times PKU can be treated by a low-phenylalanine diet; this means that in modern times $S << 1$ (or, you could say that $S \approx 0$). In this case, $\Delta q_{sel} = -Sq^2 \approx 0$ as well, and the main thing that will alter allele frequency would be the mutation rate μ. This suggests that the frequency of PKU mutant alleles should start to rise at a rate of $\mu = 10^{-4}$ |
- | ===== Example of the effect of selection on dominant mutations ===== | + | ===== Example of the effect of selection on dominant mutations: Huntington' |
- | Now let’s determine the steady state allele frequency for a dominant disease with allele frequency $q = f(A)$. In contrast to the situation for recessive alleles, selection will operate against heterozygotes for dominant alleles. For rare dominant traits, almost all affected individuals area heterozygotes; | + | Now let’s determine the steady state allele frequency for a dominant disease with allele frequency $q = f(A)$. In contrast to the situation for recessive alleles, selection will operate against heterozygotes for dominant alleles. For rare dominant traits, almost all affected individuals area heterozygotes; |
<table Tab2> | <table Tab2> | ||
<columns 100% *100%*> | <columns 100% *100%*> | ||
^ genotype | ^ genotype | ||
- | | $\frac{A}{A}$ | - | - | - | | + | | $A/A$ | - | - | - | |
- | | $\frac{A}{a}$ | $2pq \approx 2q$ | $(1-S)2q$ | + | | $A/a$ | $2pq \approx 2q$ | $(1-S)2q$ |
- | | $\frac{a}{a}$ | $p^2$ | $p^2$ | 0 | | + | | $a/a$ | $p^2$ | $p^2$ | 0 | |
</ | </ | ||
< | < | ||
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< | < | ||
- | $$\begin{aligned}\Delta q_{sel}=\frac{1}{2}\Delta f(\frac{A}{a})& | + | $$\begin{aligned}\Delta q_{sel}=\frac{1}{2}\Delta f(A/a)& |
< | < | ||
placeholder | placeholder | ||
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When $S<1$, the frequency of mutant alleles $q$ can get quite high (this makes sense mathematically; | When $S<1$, the frequency of mutant alleles $q$ can get quite high (this makes sense mathematically; | ||
- | ===== Example of the effect of selection on sex-linked mutations ===== | + | ===== Example of the effect of selection on sex-linked mutations: hemophilia A and DMD ===== |
For the final example of a balance between mutation and selection, consider an X-linked recessive disease allele with frequency $q = f(a)$. For rare alleles the vast majority of affected individuals who are operated on by selection are males, and new mutations will increase the allele frequency (i.e., $\Delta q_{mut} \approx \mu$). | For the final example of a balance between mutation and selection, consider an X-linked recessive disease allele with frequency $q = f(a)$. For rare alleles the vast majority of affected individuals who are operated on by selection are males, and new mutations will increase the allele frequency (i.e., $\Delta q_{mut} \approx \mu$). | ||
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===== Balanced polymorphisms ===== | ===== Balanced polymorphisms ===== | ||
- | Finally, we will consider a situation in which an allele is deleterious in the homozygous state but is beneficial in the heterozygous state. The steady state value of μ will be set by a balance between selection for the heterozygote and selection against the homozygote. We will need a new parameter, $h$ (the heterozygote advantage), that represents the increased reproductive fitness of heterozygote over an average individual. | + | Finally, we will consider a situation in which an allele is deleterious in the homozygous state but is beneficial in the heterozygous state. The steady state value of $q$ will be set by a balance between selection for the heterozygote and selection against the homozygote. We will need a new parameter, $h$ (the heterozygote advantage), that represents the increased reproductive fitness of heterozygote over an average individual. |
< | < | ||
<columns 100% *100%*> | <columns 100% *100%*> | ||
^ genotype | ^ genotype | ||
- | | $\frac{A}{A}$ | $p^2$ | $p^2$ | 0 | | + | | $A/A$ | $p^2$ | $p^2$ | 0 | |
- | | $\frac{A}{a}$ | $2pq \approx 2q$ | $(1+h)2q$ | + | | $A/a$ | $2pq \approx 2q$ | $(1+h)2q$ |
- | | $\frac{a}{a}$ | $q^2$ | $(1-S)q^2$ | + | | $a/a$ | $q^2$ | $(1-S)q^2$ |
</ | </ | ||
< | < | ||
- | placeholder | + | placeholder: $h$ is given as $0 \leq h \leq 1$; therefore, percent increase is given as $(1+h)$. |
</ | </ | ||
</ | </ | ||
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As before when considering dominant mutations, when we calculate $\Delta q_{sel}$ we have to halve the change in frequency for heterozygotes, | As before when considering dominant mutations, when we calculate $\Delta q_{sel}$ we have to halve the change in frequency for heterozygotes, | ||
- | $$\begin{aligned}\Delta q_{sel} & | + | $$\begin{aligned}\Delta q_{sel} & |
& | & | ||
& | & | ||
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==== Cystic fibrosis ==== | ==== Cystic fibrosis ==== | ||
- | A second example of balanced polymorphism is cystic fibrosis, a disease caused by autosomal recessive mutations in the $CFTR$ gene (__c__ystic __f__ibrosis __t__ransmembrane conductance __r__egulator). | + | A second example of balanced polymorphism is cystic fibrosis, a disease caused by autosomal recessive mutations in the $CFTR$ gene (__c__ystic __f__ibrosis __t__ransmembrane conductance __r__egulator). |
==== Lysosomal storage disorders ==== | ==== Lysosomal storage disorders ==== |
chapter_19.1725949510.txt.gz · Last modified: 2024/09/09 23:25 by mike